Esercizio. 
Risolvere la seguente equazione
![\[x-2(x+1)-3(2-x)=5[x-(3x+1)]\]](https://quisirisolve.com/wp-content/ql-cache/quicklatex.com-34e1d04c7593ce78b824df81da66064c_l3.png "Rendered by QuickLaTeX.com")
Soluzione.
Procediamo con i calcoli
Procediamo con i calcoli
![\[\begin{aligned} & x-2(x+1)-3(2-x)=5[x-(3x+1)] \quad \Leftrightarrow \quad \\\\ & \quad \Leftrightarrow \quad x-2x-2-6+3x=5(x-3x-1) \quad \Leftrightarrow \quad \\\\ & \quad \Leftrightarrow \quad x-2x-2-6+3x=5(-2x-1) \quad \Leftrightarrow \quad \\\\ & \quad \Leftrightarrow \quad x-2x-2-6+3x=-10x-5 \end{aligned}\]](https://quisirisolve.com/wp-content/ql-cache/quicklatex.com-f0db75a619007ada780ee34954c1831d_l3.png "Rendered by QuickLaTeX.com")
Ora portiamo al membro sinistro i termini con l’incognita e a destra i termini rimanenti (cioè i numeri):
![\[\begin{aligned} & x-2x-2-6+3x=-10x-5 \quad \Leftrightarrow \quad \\\\ & \quad \Leftrightarrow \quad x-2x+3x+10x = 2+6-5 \quad \Leftrightarrow \quad\\\\ & \quad \Leftrightarrow \quad 12x = 3 \quad \Leftrightarrow \quad x = \dfrac{3}{12} = \dfrac{1}{4} \end{aligned}\]](https://quisirisolve.com/wp-content/ql-cache/quicklatex.com-8ce94c19b4cf2cbcf9594081a261257c_l3.png "Rendered by QuickLaTeX.com")
Fonte: L. Sasso – I colori della Matematica (Ed. Verde)